Microsoft KB Archive/37794: Difference between revisions
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== SYMPTOMS == | == SYMPTOMS == | ||
The gcvt() function returns a value in scientific notation, without regard to the specified precision, when the floating-point value has the form "0.0<x | The gcvt() function returns a value in scientific notation, without regard to the specified precision, when the floating-point value has the form "0.0<x>" and <x> is any sequence of digits. | ||
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#include <stdio.h | #include <stdio.h> | ||
#include <stdlib.h | #include <stdlib.h> | ||
char buffer[50]; | char buffer[50]; |
Latest revision as of 10:19, 21 July 2020
Article ID: 37794
Article Last Modified on 12/12/2003
APPLIES TO
- The C Run-Time (CRT), when used with:
- Microsoft Visual C++ 1.0 Professional Edition
- Microsoft Visual C++ 1.5 Professional Edition
- Microsoft Visual C++ 1.0 Professional Edition
- Microsoft Visual C++ 2.0 Professional Edition
- Microsoft Visual C++ 4.0 Standard Edition
- Microsoft Visual C++ 5.0 Standard Edition
- Microsoft Visual C++ 6.0 Service Pack 5
This article was previously published under Q37794
SYMPTOMS
The gcvt() function returns a value in scientific notation, without regard to the specified precision, when the floating-point value has the form "0.0<x>" and <x> is any sequence of digits.
CAUSE
This is expected behavior for gcvt().
RESOLUTION
If this behavior is not desired, use the fcvt() function to convert the floating-point number to a string.
MORE INFORMATION
The following code demonstrates this behavior:
Sample Code
/* * Compile options needed: None */ #include <stdio.h> #include <stdlib.h> char buffer[50]; int precision = 20; void main(void) { gcvt(-0.1123, precision, buffer); /* Decimal output */ printf("buffer ........\"%s\"\n", buffer); gcvt(-0.0123, precision, buffer); /* Scientific notation */ printf("buffer ........\"%s\"\n", buffer); }
Keywords: kbcrt kbprb KB37794