Article ID: 174635
Article Last Modified on 7/5/2005
APPLIES TO
- Microsoft Visual C++ 5.0 Enterprise Edition
- Microsoft Visual C++ 5.0 Professional Edition
This article was previously published under Q174635
SYMPTOMS
When using _variant_t::operator IUnknown*(), the returned interface is not appropriately AddRef'd. This can cause unpredictable results when using the returned interface. For instance, subsequent calls through the interface may inexplicably fail or may cause an Access Violation.
RESOLUTION
Write a function to convert a _variant_t to an IUnknown*. A method based on _variant_t::operator IDispatch*() is shown in the sample below.
STATUS
Microsoft has confirmed this to be a bug in the Microsoft products listed at the beginning of this article. This bug has been fixed in Visual Studio 97 Service Pack 3 and Visual C++ version 6.0.
For more information, please see the following article in the Microsoft Knowledge Base:
170365 INFO: Visual Studio 97 Service Packs - What, Where, and Why
MORE INFORMATION
The code below should be called instead of allowing _variant_t::operator IUnknown*() to be implicitly called to work around this problem. The conversion operator will be called whenever a conversion from _variant_t to IUnknown* is required. One place this occurs is with assignment statements, another is passing a _variant_t to a function that expects an IUnknown*.
Sample
IUnknown* f( const _variant_t & vt ) { if (V_VT(&vt) == VT_UNKNOWN) { V_UNKNOWN(&vt)->AddRef(); return V_UNKNOWN(&vt); } _variant_t vttmp; vttmp.ChangeType(VT_UNKNOWN, &vt); V_UNKNOWN(&vttmp)->AddRef(); return V_UNKNOWN(&vttmp); } void g() { _variant_t vt; IUnknown * punk=0; // ...some code... punk = vt; // will cause _variant_t::operator IUnknown*() // to be called. Comment this out. //punk = f(vt); // call f instead. Uncomment for workaround // ...more code... }
Additional query words: refcount Release
Keywords: kbbug kbfix kbvc600fix kbvs97sp2fix KB174635