Microsoft KB Archive/168799: Difference between revisions
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S = Trim$(Left$(S, P - 1)) | S = Trim$(Left$(S, P - 1)) |
Revision as of 20:31, 20 July 2020
Article ID: 168799
Article Last Modified on 1/19/2007
APPLIES TO
- Microsoft Visual Basic 5.0 Control Creation Edition
- Microsoft Visual Basic 5.0 Learning Edition
- Microsoft Visual Basic 5.0 Professional Edition
- Microsoft Visual Basic 5.0 Enterprise Edition
- Microsoft Visual Basic 4.0 Standard Edition
- Microsoft Visual Basic 4.0 Professional Edition
- Microsoft Visual Basic 4.0 Professional Edition
- Microsoft Visual Basic 4.0 16-bit Enterprise Edition
- Microsoft Visual Basic 4.0 32-Bit Enterprise Edition
- Microsoft Visual Basic 2.0 Standard Edition
- Microsoft Visual Basic 3.0 Professional Edition
- Microsoft Visual Basic 2.0 Professional Edition
- Microsoft Visual Basic 3.0 Professional Edition
- Microsoft Access 1.0 Standard Edition
- Microsoft Access 1.1 Standard Edition
- Microsoft Access 2.0 Standard Edition
- Microsoft Access 95 Standard Edition
- Microsoft Access 97 Standard Edition
- Microsoft Excel 97 Standard Edition
- Microsoft Word 97 Standard Edition
- Microsoft PowerPoint 97 Standard Edition
This article was previously published under Q168799
SUMMARY
This article provides a procedure for parsing a single variable containing a person's name into up to 6 parts:
Title (Mr., Ms., etc.) First Name Middle Initial(s) Last Name Pedigree (Jr., Sr., III, etc.) Degree(s) (B.S., PhD, etc.)
MORE INFORMATION
WARNING: ANY USE BY YOU OF THE CODE/MACRO PROVIDED IN THIS ARTICLE IS AT YOUR OWN RISK. Microsoft provides this code/macro "as is" without warranty of any kind, either express or implied, including but not limited to the implied warranties of merchantability and/or fitness for a particular purpose.
NOTE: In the following sample code, an underscore (_) at the end of a line is used as a line-continuation character. For versions of BASIC that don't support line-continuation characters, remove the underscore from the end of the line and merge with the following line when re-creating this code.
Fields are parsed and removed from the name in the following order:
Title - (if the first word matches the list of standard titles)
Degree - (anything after the first comma)
Pedigree - (if the last word matches the list of standard pedigrees)
Last Name - (must not contain spaces, but can be hyphenated)
First Name - (must not contain spaces)
Middle Initial(s) - (the remainder)
Step-by-Step Example
Enter the following code:
Function CutLastWord (ByVal S As String, Remainder As String) _ As String ' CutLastWord: returns the last word in S. ' Remainder: returns the rest. ' ' Words are separated by spaces ' Dim I As Integer, P As Integer S = Trim$(S) P = 1 For I = Len(S) To 1 Step -1 If Mid$(S, I, 1) = " " Then P = I + 1 Exit For End If Next I If P = 1 Then CutLastWord = S Remainder = "" Else CutLastWord = Mid$(S, P) Remainder = Trim$(Left$(S, P - 1)) End If End Function Function CutWord (ByVal S As String, Remainder As String) As String ' ' CutWord: returns the first word in S. ' Remainder: returns the rest. ' Dim P As Integer S = Trim$(S) P = InStr(S, " ") If P = 0 Then P = Len(S) + 1 CutWord = Left$(S, P - 1) Remainder = Trim$(Mid$(S, P + 1)) End Function Sub ParseName (ByVal S As String, Title As String, FName As String, _ MName As String, LName As String, _ Pedigree As String, Degree As String) Dim Word As String, P As Integer, Found As Integer Const Titles = "Mr.Mrs.Ms.Dr.Miss,Sir,Madam,Mayor,President" Const Pedigrees = "Jr.Sr.III,IV,VIII,IX,XIII" Title = "" FName = "" MName = "" LName = "" Pedigree = "" Degree = "" ' ' Get Title ' Word = CutWord(S, S) If InStr(Titles, Word) Then Title = Word Else S = Word & " " & S End If ' ' Get Degree ' P = InStr(S, ",") If P > 0 Then Degree = Trim$(Mid$(S, P + 1)) S = Trim$(Left$(S, P - 1)) End If ' ' Get Pedigree ' Word = CutLastWord(S, S) If InStr(Pedigrees, Word) Then Pedigree = Word Else S = S & " " & Word End If ' ' Get the rest ' LName = CutLastWord(S, S) ' Last Name FName = CutWord(S, S) ' First Name MName = Trim(S) ' Initials/Middle Name(s) End Sub
To test, create a form with seven text boxes (txtName, txtTitle, txtFirstName, txtMI, txtLastName, txtPedigree, txtDegree), and a command button. Add the following code:
Sub Command1_Click() Dim Title As String, FName As String, MI As String Dim LName As String, Pedigree As String, Degree As String ParseName txtName, Title, FName, MI, LName, Pedigree, Degree txtTitle = Title txtFirstName = FName txtMI = MI txtLastName = LName txtPedigree = Pedigree txtDegree = Degree End Sub
- Display the form, type a name into txtName, and click the command button. The other six fields should contain the parsed values.
Additional Information
Other notes, limitations, and suggestions for improvement (left to the reader's devices):
- The parsing routine assumes a comma before the Degree but not before the Pedigree. If there is a comma before the Pedigree, it will be included as part of the Degree(s). If you want to allow the Pedigree to be preceded by a comma, you can add an additional check to see if the first word (comma separated) of the Degree is in the list of standard Pedigrees.
- The first and last names are assumed to contain no spaces. If they do (e.g. Mary Beth Saint John), part of the name (e.g. Beth Saint) will end up in the Middle Initial/Middle Name return value. Unfortunately, due to the high variability of this case, there is no good workaround other than manual intervention.
- The parsing routine is designed for English/American names. Other languages may have different conventions that may require adjustments to the parsing code.
- The list of standard Titles and Pedigrees may be easily extended by adding entries to the two Const declarations in ParseName.
- The check for Title can be made more generic by looking for a period at the end of the first word if it is not already in the list of standard Titles.
Keywords: kbhowto kbprogramming KB168799