Article ID: 159093
Article Last Modified on 11/1/2006
APPLIES TO
- Microsoft Windows NT Workstation 4.0 Developer Edition
- Microsoft Windows NT Server 4.0 Standard Edition
This article was previously published under Q159093
SYMPTOMS
Muldiv(0,0,-1) returns -1 when it should be 0. The MulDiv function multiplies two 32-bit values and then divides the 64-bit result by a third 32-bit value. The return value is rounded up or down to the nearest integer.
int MulDiv(
int nNumber, // 32-bit signed multiplicand
int nNumerator, // 32-bit signed multiplier
int nDenominator // 32-bit signed divisor
Parameters
nNumber: Specifies the multiplicand.
nNumerator: Specifies the multiplie
nDenominator: Specifies the number by which the result of the multiplication (nNumber * nNumerator) is to be divided.
Return Values
If the function succeeds, the return value is the result of the multiplication and division. If either an overflow occurred or nDenominator was 0, the return value is -1.
CAUSE
The multiplier is positive, the multiplicand is positive, the divisor is negative. The result is negative when actually, the result was positive (0).
STATUS
Microsoft has confirmed this to be a problem in Microsoft Windows NT version 4.0. This problem was corrected in the latest Microsoft Windows NT 4.0 U.S. Service Pack. For information on obtaining the service pack, query on the following word in the Microsoft Knowledge Base (without the spaces):
S E R V P A C K
Additional query words: prodnt
Keywords: kbenv KB159093
