Article ID: 119083
Article Last Modified on 1/19/2007
APPLIES TO
- Microsoft Excel 2000 Standard Edition
- Microsoft Excel 2002 Standard Edition
- Microsoft Excel 97 Standard Edition
This article was previously published under Q119083
For a Microsoft Excel 2001 or Microsoft Excel 98 version of this article, see 119083.
SYMPTOMS
The MOD() function in Microsoft Excel may return a #NUM! error value instead of a valid remainder (modulus).
CAUSE
The MOD() function returns the #NUM! error if the following condition is true:
(divisor * 134217728) is less than or equal to number
WORKAROUND
If the above condition is true, and the MOD() function returns a #NUM! error, you can use the following formula to calculate the remainder (modulus) of two numbers:
=number-(INT(number/divisor)*divisor)
For example, instead of using this formula
=MOD(J13,K13)
use this formula:
=J13-(INT(J13/K13)*K13)
MORE INFORMATION
In Microsoft Excel, the MOD() function returns the remainder (modulus) of dividing one number by another. The MOD() function accepts two arguments:
Argument Definition
--------------------------------------
Number The number being divided
Divisor The number being divided by
If you want to calculate the remainder (modulus) of 22 divided by 5, you would use the following formula:
=MOD(22,5)
The result is 2 (22 divided by 5 leaves a remainder of 2).
If the divisor argument, multiplied by 134,217,728 (or 2 raised to the 27th power), is less than or equal to the number argument, the MOD() function returns a #NUM! error value.
Additional query words: 7.00
Keywords: kbprb KB119083
