Article ID: 279293
Article Last Modified on 10/9/2003
APPLIES TO
- Microsoft SQL Server 2000 Standard Edition
This article was previously published under Q279293
BUG #: 350799 (shiloh_bugs)
SYMPTOMS
A Transact-SQL SELECT statement that uses a CASE function with a LIKE comparison against an empty string can fail with an access violation (AV). In some cases, this can cause SQL Server to be shut down abnormally.
RESOLUTION
To resolve this problem, obtain the latest service pack for Microsoft SQL Server 2000. For additional information, click the following article number to view the article in the Microsoft Knowledge Base:
290211 INF: How to Obtain the Latest SQL Server 2000 Service Pack
Hotfix
NOTE: The following hotfix was created prior to Microsoft SQL Server 2000 Service Pack 1.
The English version of this fix should have the following file attributes or later:
Version File name Platform
---------------------------------------
8.00.217 S80217i.exe Intel
NOTE: Due to file dependencies, the most recent hotfix or feature that contains the above files may also contain additional files.
WORKAROUND
Because the problem only occurs when using LIKE with an empty string constant value (that is, ), use the "=" operator because LIKE and "=" produce the same results if no pattern matching characters (such as "%") exist in the expression.
STATUS
Microsoft has confirmed that this is a problem in Microsoft SQL Server 2000. This problem was first corrected in SQL Server 2000 Service Pack 1.
MORE INFORMATION
The following is an example SELECT statement that will encounter this problem:
select city = CASE WHEN city like '' THEN NULL ELSE city END,
address = CASE WHEN address like '' THEN NULL ELSE address END
from authors
In this case, to work around the problem, change this query to:
select city = CASE WHEN city = '' THEN NULL ELSE city END,
address = CASE WHEN address = '' THEN NULL ELSE address END
from authors
Additional query words: terminate terminates terminated
Keywords: kbbug kbfix kbqfe kbsqlserv2000sp1fix KB279293
