Article ID: 153801
Article Last Modified on 12/8/2003
APPLIES TO
- Microsoft Visual C++ 4.0 Standard Edition
- Microsoft Visual C++ 4.1 Subscription
- Microsoft Visual C++ 4.2 Professional Edition
- Microsoft Visual C++ 5.0 Enterprise Edition
- Microsoft Visual C++ 5.0 Professional Edition
This article was previously published under Q153801
SYMPTOMS
When you attempt to build the sample code below, you will get an error message similar to the following:
CAUSE
This behavior occurs because you are attempting to access a member of a nested class that has been used as a base class. It is valid to do this. The compiler should not be reporting an error, and, in this case, the error that is being reported is misleading.
RESOLUTION
To work around the problem, you can use a typedef to refer to the nested class that is being used as a base class. This is illustrated in the sample code below.
STATUS
Microsoft has confirmed this to be a bug in the Microsoft products listed at the beginning of this article. We are researching this problem and will post new information here in the Microsoft Knowledge Base as it becomes available.
MORE INFORMATION
Sample Code
/* Compile options needed: none
*/
The following code reproduces the problem:
class A
{
public:
class AA
{
public:
void m();
};
};
class B : public A::AA
{
public:
void m() { A::AA::m(); }
};
void main()
{
B b;
}
The following code works around the problem (note the use of the typedef):
class A
{
public:
class AA
{
public:
void m();
};
};
typedef A::AA NestedBase;
class B : public NestedBase
{
public:
void m() { NestedBase::m(); }
};
void main()
{
B b;
}
Additional query words: kbVC400bug 10.00 10.10 10.20
Keywords: kbbug kblangcpp kbcpponly kbcompiler KB153801
