Microsoft KB Archive/246474
Article ID: 246474
Article Last Modified on 3/14/2006
- Microsoft SQL Server 7.0 Standard Edition
This article was previously published under Q246474
BUG #: 56775 (SQLBUG_70)
When executing a query with a WHERE clause that references a date column that has a clustered index and any other column having a non-clustered index, SQL Server may choose an inefficient clustered index resulting in excessive response time to the user.
The optimizer chooses an inefficient clustered index. Forcing a non-clustered index gives much better performance in a simple SELECT statement with 2 search arguments (SARGs), one of which is a DATE range.
If a table has a clustered index on date column (column1) and non-clustered index on any other column (column2) and you perform a simple SELECT on the table with WHERE condition BETWEEN date range (column1) AND column2 = 'value' like this:
select * from table1 where column1 between 'date1' and 'date2' and column2 = 'value'
The optimizer choses the clustered index on column1 even though use of a non-clustered index on column2 gives better performance. That is, less CPU time and logical reads.
Force the non-clustered index using a table hint.
Microsoft has confirmed this to be a problem in SQL Server 7.0. This problem has been corrected in U.S. Service Pack 2 for Microsoft SQL Server 7.0. For more information, click the following article number to view the article in the Microsoft Knowledge Base:
254561 INF: How to Obtain Service Pack 2 for Microsoft SQL Server 7.0 and Microsoft Data Engine (MSDE) 1.0
For more information, contact your primary support provider.
Keywords: kbbug kbfix KB246474