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Microsoft KB Archive/171545

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Knowledge Base

Article ID: 171545

Article Last Modified on 2/16/2005


  • Microsoft Visual Basic 5.0 Professional Edition
  • Microsoft Visual Basic 5.0 Enterprise Edition

This article was previously published under Q171545


Using the CreateInterface's optional "Default" flag results in it not making an interface the default interface for its class.


Microsoft has confirmed this to be a bug in the Microsoft products listed at the beginning of this article. This bug has been fixed in Visual Studio 97 Service Pack 3.

For more information, please see the following article in the Microsoft Knowledge Base:

170365 INFO: Visual Studio 97 Service Packs - What, Where, and Why

For a list of the Visual Basic 5.0 bugs that were fixed in the Visual Studio 97 Service Pack 3, please see the following article in the Microsoft Knowledge Base:

175450 INFO: Visual Basic 5.0 Fixes in Visual Studio 97 Service Pack 3


Step-by-Step Example

  1. Start a new transaction in Visual Basic.
  2. Create a new TIM class.
  3. Create an interface off the new TIM class using "IClassDef::CreateInterface". Set the interface to be the default interface for this class by passing in "Default" as the value of the optional parameter.
  4. Create at least one property and attach it to the new interface.
  5. Commit the transaction to save the new TIM.
  6. Create an object instance based on the newly-defined class.
  7. Try to access the property off the default interface using the following format: "Value = Object.Property."


No error.


Error number: 438
Error description: Object doesn't support this property or method.

Keywords: kbbug kbfix kbvs97sp2fix kbvbp500sp3fix KB171545