Microsoft KB Archive/158580

= How to use the set::swap, set::begin and set::end Standard Template Library (STL) functions in Visual C++ =

Article ID: 158580

Article Last Modified on 7/15/2005

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APPLIES TO

 The Standard C++ Library, when used with:  Microsoft Visual C++ 4.2 Enterprise Edition

 Microsoft Visual C++ 5.0 Enterprise Edition

 Microsoft Visual C++ 6.0 Enterprise Edition

 Microsoft Visual C++ 4.2 Professional Edition</li></ul>

 Microsoft Visual C++ 5.0 Professional Edition</li></ul>

 Microsoft Visual C++ 6.0 Professional Edition</li></ul>

 Microsoft Visual C++ 6.0 Standard Edition</li></ul>

 Microsoft Visual C++ .NET 2002 Standard Edition</li></ul>

 Microsoft Visual C++ .NET 2003 Standard Edition</li></ul> </li></ul>

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This article was previously published under Q158580

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Note Microsoft Visual C++ NET (2002) supported both the managed code model that is provided by the .NET Framework and the unmanaged native Windows code model. The information in this article applies to unmanaged Visual C++ code only.

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SUMMARY
The following sample code illustrates how to use the set::swap, set::begin and set::end STL functions in Visual C++.

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Prototype
template<class _K, class _Pr, class _A> class set { public: // Function 1:

void swap(_Myt& _X); // Function 2: friend void swap(_Myt& _X, _Myt& _Y); // Function 3: const_iterator begin const; // Function 4: const_iterator end const; } Note The class/parameter names in the prototype may not match the version in the header file. Some have been modified to improve readability.

Description
The swap function swaps the two controlled sequences. The begin function returns a bidirectional iterator that points at the first element of the sequence. The end function returns a bidirectional iterator that points just beyond the end of the sequence.

Sample code
////////////////////////////////////////////////////////////////////// // // Compile options needed: -GX // // SetSwapBeginEnd.cpp: //     Illustrates how to use the swap function to exchange the two //     controlled sequences. It also illustrates how to use the //     begin function to get a bidirectional iterator that points at //      the first element of the controlled sequence. Finally, it //     illustrates how to use the end function to get a bidirectional //     iterator that points just beyond the end of the controlled //     sequence. // // Functions: // //   swap        Exchanges the two controlled sequences. //   begin       Returns a bidirectional iterator that points at the //               first element of the controlled sequence. //   end         Returns a bidirectional iterator that points just //               beyond the end of the controlled sequence. // // Written by Derek Jamison // of Microsoft Technical Support, // Copyright (c) 1996 Microsoft Corporation. All rights reserved. //////////////////////////////////////////////////////////////////////


 * 1) pragma warning(disable:4786)


 * 1) include
 * 2) include

using namespace std; // std c++ libs implemented in std #endif
 * 1) if _MSC_VER > 1020  // if VC++ version is > 4.2

typedef set<int,less ,allocator > SET_INT;

void main {

SET_INT s1; SET_INT s2; SET_INT::iterator i; cout << "s1.insert(5)" << endl; s1.insert(5); cout << "s1.insert(10)" << endl; s1.insert(10); cout << "s1.insert(15)" << endl; s1.insert(15); cout << "s2.insert(2)" << endl; s2.insert(2); cout << "s2.insert(4)" << endl; s2.insert(4);

cout << "swap(s1,s2)" << endl; swap(s1,s2);

// Displays: 2,4

for (i=s1.begin;i!=s1.end;i++)

cout << "s1 has " << *i << " in its set." << endl;

// Displays: 5,10,15

for (i=s2.begin;i!=s2.end;i++)

cout << "s2 has " << *i << " in its set." << endl;

cout << "s1.swap(s2)" << endl; s1.swap(s2);

// Displays: 5,10,15

for (i=s1.begin;i!=s1.end;i++)

cout << "s1 has " << *i << " in its set." << endl;

// Displays: 2,4

for (i=s2.begin;i!=s2.end;i++)

cout << "s2 has " << *i << " in its set." << endl;

}

Program output
s1.insert(5) s1.insert(10) s1.insert(15) s2.insert(2) s2.insert(4) swap(s1,s2) s1 has 2 in its set. s1 has 4 in its set. s2 has 5 in its set. s2 has 10 in its set. s2 has 15 in its set. s1.swap(s2) s1 has 5 in its set. s1 has 10 in its set. s1 has 15 in its set. s2 has 2 in its set. s2 has 4 in its set.

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