Microsoft KB Archive/926503

= In Windows Workflow Foundation, the selection in the IntelliSense list is not displayed in the Conditions box when you press the EQUAL SIGN (=) key in the Rule Condition Editor =

Article ID: 926503

Article Last Modified on 11/24/2006

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APPLIES TO


 * Windows Workflow Foundation

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SYMPTOMS
Consider the following scenario. In Microsoft Windows Workflow Foundation, you start to type an expression in the Rule Condition Editor. The Microsoft IntelliSense list appears, and you press the EQUAL SIGN (=) key to select the expression in the IntelliSense list. In this scenario, the selection in the IntelliSense list is not entered in the Conditions box.



CAUSE
This problem occurs because the Rule Condition Editor does not use Microsoft Visual Studio 2005 IntelliSense. Therefore, the IntelliSense settings do not apply to the Rule Condition Editor.



WORKAROUND
To work around this problem, press ENTER to select the expression in the IntelliSense list.



STATUS
Microsoft has confirmed that this is a problem in the Microsoft products that are listed in the &quot;Applies to&quot; section.



Steps to reproduce the problem

 * 1) In Visual Studio 2005, create a Windows Workflow Foundation project.

Note You must have Visual Studio 2005 Extensions for Windows Workflow Foundation installed.
 * 1) Add an activity, and then add an IfElse control in the activity.
 * 2) Click the left branch of the IfElse control.
 * 3) In the Property dialog box, click Declarative Rule Condition in the Condition list.
 * 4) Next to ConditionName, click the ellipsis button (...).
 * 5) In the Select Condition dialog box, click New Condition.
 * 6) In the Conditions box, type this.Act, and then press the EQUAL SIGN.

When you do this, the this.Activities expression is not displayed in the Conditions box.

Keywords: kbtshoot kbprb KB926503

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