Microsoft KB Archive/68921

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BUG: Using float/double Function as Subscript Causes Bad Code

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Q68921

6.00 6.00a 6.00ax 7.00 | 6.00 6.00a | 1.00 1.50 MS-DOS | OS/2 | WINDOWS kbtool kbbuglist -- The information in this article applies to: - The Microsoft C/C++ Compiler (CL.EXE) included with: - Microsoft C for MS-DOS, versions 6.0, 6.0a, and 6.0ax - Microsoft C for OS/2, versions 6.0 and 6.0a - Microsoft C/C++ for MS-DOS, version 7.0 - Microsoft Visual C++ for Windows, versions 1.0 and 1.5 -- SYMPTOMS ======== Multiple calls to float functions in the same logical statement may cause the floating-point accumulator to be overwritten if the result of one of the calls is used as a subscript. This problem may occur with the Microsoft C Compiler versions 6.0, 6.0a, and 6.0ax, but does not occur when the /qc (quick compile) option is specified. RESOLUTION ========== This problem occurs because of the C convention for returning floating point values. To ensure that this problem never occurs, you need to change the usual order of evaluation rules. One way to resolve this problem is to use the PASCAL calling convention. NOTE: C/C++ 7.0 works with this particular piece of code, however, it is possible that this problem will occur with other samples. STATUS ====== Microsoft has confirmed this to be a problem in the products listed at the beginning of this article. MORE INFORMATION ================ The sample code below illustrates this problem. Function f_one returns 0.0 in the floating-point accumulator (__fac). However, the floating-point accumulator is not saved before f_two is called. The function f_two returns 12.0 in __fac, which overwrites the 0.0 returned by f_one. As a result, array[12] is changed, instead of array[0]. As a workaround, the function's return value may be stored in a temporary variable, or the two functions may be declared as _pascal. Sample Code --- /* Compile options needed: none */ #include float f_one(void); float f_two(void); float fval[20]; void main(void) { int i; // This doesn't work. fval[(int)f_one] = f_two; printf(&quot;fval[0] (should equal 12.0) = %f\n&quot;, fval[0]); // This works. i = (int)f_one; fval[i] = f_two; printf(&quot;fval[0] (should equal 12.0) = %f\n&quot;, fval[0]); } float f_one { return((float)0.0); } float f_two { return((float)12.0); } Additional reference words: 1.00 1.50 6.00 6.00a 6.00ax 7.00 8.00 8.00c KBCategory: kbtool kbbuglist KBSubcategory: CLIss

Keywords : kb16bitonly

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Technology : kbVCsearch kbAudDeveloper kbCVCComp