Microsoft KB Archive/150127

= BUG: PEEKCHARQQ Fails in QuickWin or Standard Graphics Program =

Article ID: 150127

Article Last Modified on 10/17/2003

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APPLIES TO


 * Microsoft FORTRAN PowerStation 32
 * Microsoft FORTRAN PowerStation 4.0 Standard Edition

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This article was previously published under Q150127



SYMPTOMS
Using the PEEKCHARQQ run-time function to check the keystroke buffer for keyboard characters will fail, causing .false. to be returned as the function's result.



RESOLUTION


STATUS
Microsoft has confirmed this to be a bug in the Microsoft products listed at the beginning of this article. We are researching this problem and will post new information here in the Microsoft Knowledge Base as it becomes available.



Steps to Reproduce Problem

 * 1) Using the sample code listed below, create a QuickWin or Standard Graphics application.
 * 2) Run the application. Running the application causes the message "Press any key to exit" to be displayed 100 times. Then the application quits.

NOTE: Pressing any key does not halt the application because PEEKCHARQQ always returns .false. in a QuickWin or Standard Graphics program.

Sample Code
! Compile options needed: /MW or /MWs

INCLUDE 'FLIB.FI' INCLUDE 'FLIB.FD'

INTEGER COUNT LOGICAL DONE

COUNT = 0 DONE = .FALSE.

10   DO WHILE( (.NOT. DONE) .AND. (COUNT .LT. 100) )        WRITE(*, *) 'Press any key to exit' IF ( PEEKCHARQQ ) THEN DONE = .TRUE. GOTO 10 END IF        COUNT = COUNT + 1 END DO     WRITE(*,*) 'Program terminated...' END

Keywords: kbbug kblangfortran kbprogramming KB150127

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